At 9 a.m., George started from City U and travelled towards City V and his speed remained constant throughout. At 10 a.m., Penelope started her journey from City U towards City V at an average speed of 88 km/h. Penelope overtook George at 1 p.m. After overtaking, Penelope carried on her journey at the same average speed and reached at City V at 2:45 p.m.

1. Find George's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Penelope had travelled until Penelope overtook George
= 3 x 88
= 264 km

From 9 a.m. to 1 p.m. = 4 h

George's average speed
= 264 ÷ 4
= 66 km/h

(b)
From 10 a.m. to 2:45 p.m. = 4 h 45 min

1 h = 60 min
4 h 45 min = 4 ⁴⁵ ₆₀
 h = 4 ³₄ h

Distance between the two cities
= 4 ³₄ x 88
= ¹⁹₄ x 88
= 418 km

Answer(s): (a) 66 km/h; (b) 418 km