At 8 a.m., Ahmad started from City Y and travelled towards City Z and his speed remained constant throughout. At 10 a.m., Cindy started her journey from City Y towards City Z at an average speed of 70 km/h. Cindy overtook Ahmad at 1 p.m. After overtaking, Cindy carried on her journey at the same average speed and reached at City Z at 4:30 p.m.

1. Find Ahmad's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Cindy had travelled until Cindy overtook Ahmad
= 3 x 70
= 210 km

From 8 a.m. to 1 p.m. = 5 h

Ahmad's average speed
= 210 ÷ 5
= 42 km/h

(b)
From 10 a.m. to 4:30 p.m. = 6 h 30 min

1 h = 60 min
6 h 30 min = 6 ³⁰ ₆₀
 h = 6 ¹₂ h

Distance between the two cities
= 6 ¹₂ x 70
= ¹³₂ x 70
= 455 km

Answer(s): (a) 42 km/h; (b) 455 km