At 7 a.m., Fred started from City S and travelled towards City T and his speed remained constant throughout. At 9 a.m., Anna started her journey from City S towards City T at an average speed of 84 km/h. Anna overtook Fred at 1 p.m. After overtaking, Anna carried on her journey at the same average speed and reached at City T at 3:30 p.m.

1. Find Fred's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 1 p.m. = 4 h

Distance that Anna had travelled until Anna overtook Fred
= 4 x 84
= 336 km

From 7 a.m. to 1 p.m. = 6 h

Fred's average speed
= 336 ÷ 6
= 56 km/h

(b)
From 9 a.m. to 3:30 p.m. = 6 h 30 min

1 h = 60 min
6 h 30 min = 6 ³⁰ ₆₀
 h = 6 ¹₂ h

Distance between the two cities
= 6 ¹₂ x 84
= ¹³₂ x 84
= 546 km

Answer(s): (a) 56 km/h; (b) 546 km