At 7 a.m., Eric started from City K and travelled towards City L and his speed remained constant throughout. At 10 a.m., Gabby started her journey from City K towards City L at an average speed of 84 km/h. Gabby overtook Eric at 1 p.m. After overtaking, Gabby carried on her journey at the same average speed and reached at City L at 4:40 p.m.
- Find Eric's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Gabby had travelled until Gabby overtook Eric
= 3 x 84
= 252 km
From 7 a.m. to 1 p.m. = 6 h
Eric's average speed
= 252 ÷ 6
= 42 km/h
(b)
From 10 a.m. to 4:40 p.m. = 6 h 40 min
1 h = 60 min
6 h 40 min = 6
40 60
h = 6
23 h
Distance between the two cities
= 6
23 x 84
=
203 x 84
= 560 km
Answer(s): (a) 42 km/h; (b) 560 km