At 9 a.m., Caden started from City K and travelled towards City L and his speed remained constant throughout. At 10 a.m., Cindy started her journey from City K towards City L at an average speed of 66 km/h. Cindy overtook Caden at 3 p.m. After overtaking, Cindy carried on her journey at the same average speed and reached at City L at 6:50 p.m.

1. Find Caden's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 3 p.m. = 5 h

Distance that Cindy had travelled until Cindy overtook Caden
= 5 x 66
= 330 km

From 9 a.m. to 3 p.m. = 6 h

Caden's average speed
= 330 ÷ 6
= 55 km/h

(b)
From 10 a.m. to 6:50 p.m. = 8 h 50 min

1 h = 60 min
8 h 50 min = 8 ⁵⁰ ₆₀
 h = 8 ⁵₆ h

Distance between the two cities
= 8 ⁵₆ x 66
= ⁵³₆ x 66
= 583 km

Answer(s): (a) 55 km/h; (b) 583 km