At 9 a.m., Flynn started from City V and travelled towards City W and his speed remained constant throughout. At 10 a.m., Rachel started her journey from City V towards City W at an average speed of 90 km/h. Rachel overtook Flynn at 3 p.m. After overtaking, Rachel carried on her journey at the same average speed and reached at City W at 6:20 p.m.

1. Find Flynn's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 3 p.m. = 5 h

Distance that Rachel had travelled until Rachel overtook Flynn
= 5 x 90
= 450 km

From 9 a.m. to 3 p.m. = 6 h

Flynn's average speed
= 450 ÷ 6
= 75 km/h

(b)
From 10 a.m. to 6:20 p.m. = 8 h 20 min

1 h = 60 min
8 h 20 min = 8 ²⁰ ₆₀
 h = 8 ¹₃ h

Distance between the two cities
= 8 ¹₃ x 90
= ²⁵₃ x 90
= 750 km

Answer(s): (a) 75 km/h; (b) 750 km