At 7 a.m., Zane started from City E and travelled towards City F and his speed remained constant throughout. At 9 a.m., Pamela started her journey from City E towards City F at an average speed of 72 km/h. Pamela overtook Zane at 1 p.m. After overtaking, Pamela carried on her journey at the same average speed and reached at City F at 5:25 p.m.

1. Find Zane's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 1 p.m. = 4 h

Distance that Pamela had travelled until Pamela overtook Zane
= 4 x 72
= 288 km

From 7 a.m. to 1 p.m. = 6 h

Zane's average speed
= 288 ÷ 6
= 48 km/h

(b)
From 9 a.m. to 5:25 p.m. = 8 h 25 min

1 h = 60 min
8 h 25 min = 8 ²⁵ ₆₀
 h = 8 ⁵₁₂ h

Distance between the two cities
= 8 ⁵₁₂ x 72
= ¹⁰¹₁₂ x 72
= 606 km

Answer(s): (a) 48 km/h; (b) 606 km