At 7 a.m., Albert started from City D and travelled towards City E and his speed remained constant throughout. At 10 a.m., Anna started her journey from City D towards City E at an average speed of 84 km/h. Anna overtook Albert at 1 p.m. After overtaking, Anna carried on her journey at the same average speed and reached at City E at 1:35 p.m.
- Find Albert's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Anna had travelled until Anna overtook Albert
= 3 x 84
= 252 km
From 7 a.m. to 1 p.m. = 6 h
Albert's average speed
= 252 ÷ 6
= 42 km/h
(b)
From 10 a.m. to 1:35 p.m. = 3 h 35 min
1 h = 60 min
3 h 35 min = 3
35 60
h = 3
712 h
Distance between the two cities
= 3
712 x 84
=
4312 x 84
= 301 km
Answer(s): (a) 42 km/h; (b) 301 km