At 8 a.m., Owen started from City A and travelled towards City B and his speed remained constant throughout. At 10 a.m., Tammy started her journey from City A towards City B at an average speed of 72 km/h. Tammy overtook Owen at 2 p.m. After overtaking, Tammy carried on her journey at the same average speed and reached at City B at 1:45 p.m.

1. Find Owen's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Tammy had travelled until Tammy overtook Owen
= 4 x 72
= 288 km

From 8 a.m. to 2 p.m. = 6 h

Owen's average speed
= 288 ÷ 6
= 48 km/h

(b)
From 10 a.m. to 1:45 p.m. = 3 h 45 min

1 h = 60 min
3 h 45 min = 3 ⁴⁵ ₆₀
 h = 3 ³₄ h

Distance between the two cities
= 3 ³₄ x 72
= ¹⁵₄ x 72
= 270 km

Answer(s): (a) 48 km/h; (b) 270 km