At 9 a.m., Seth started from City W and travelled towards City X and his speed remained constant throughout. At 10 a.m., Joelle started her journey from City W towards City X at an average speed of 80 km/h. Joelle overtook Seth at 2 p.m. After overtaking, Joelle carried on her journey at the same average speed and reached at City X at 2:45 p.m.
- Find Seth's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 2 p.m. = 4 h
Distance that Joelle had travelled until Joelle overtook Seth
= 4 x 80
= 320 km
From 9 a.m. to 2 p.m. = 5 h
Seth's average speed
= 320 ÷ 5
= 64 km/h
(b)
From 10 a.m. to 2:45 p.m. = 4 h 45 min
1 h = 60 min
4 h 45 min = 4
45 60
h = 4
34 h
Distance between the two cities
= 4
34 x 80
=
194 x 80
= 380 km
Answer(s): (a) 64 km/h; (b) 380 km