At 7 a.m., Henry started from City Z and travelled towards City A and his speed remained constant throughout. At 8 a.m., Penelope started her journey from City Z towards City A at an average speed of 72 km/h. Penelope overtook Henry at 1 p.m. After overtaking, Penelope carried on her journey at the same average speed and reached at City A at 1:50 p.m.

1. Find Henry's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 8 a.m. to 1 p.m. = 5 h

Distance that Penelope had travelled until Penelope overtook Henry
= 5 x 72
= 360 km

From 7 a.m. to 1 p.m. = 6 h

Henry's average speed
= 360 ÷ 6
= 60 km/h

(b)
From 8 a.m. to 1:50 p.m. = 5 h 50 min

1 h = 60 min
5 h 50 min = 5 ⁵⁰ ₆₀
 h = 5 ⁵₆ h

Distance between the two cities
= 5 ⁵₆ x 72
= ³⁵₆ x 72
= 420 km

Answer(s): (a) 60 km/h; (b) 420 km