At 8 a.m., Will started from City G and travelled towards City H and his speed remained constant throughout. At 10 a.m., Vanessa started her journey from City G towards City H at an average speed of 72 km/h. Vanessa overtook Will at 2 p.m. After overtaking, Vanessa carried on her journey at the same average speed and reached at City H at 3:20 p.m.

1. Find Will's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Vanessa had travelled until Vanessa overtook Will
= 4 x 72
= 288 km

From 8 a.m. to 2 p.m. = 6 h

Will's average speed
= 288 ÷ 6
= 48 km/h

(b)
From 10 a.m. to 3:20 p.m. = 5 h 20 min

1 h = 60 min
5 h 20 min = 5 ²⁰ ₆₀
 h = 5 ¹₃ h

Distance between the two cities
= 5 ¹₃ x 72
= ¹⁶₃ x 72
= 384 km

Answer(s): (a) 48 km/h; (b) 384 km