At 8 a.m., Eric started from City V and travelled towards City W and his speed remained constant throughout. At 9 a.m., Yoko started her journey from City V towards City W at an average speed of 80 km/h. Yoko overtook Eric at 1 p.m. After overtaking, Yoko carried on her journey at the same average speed and reached at City W at 6:45 p.m.
- Find Eric's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 1 p.m. = 4 h
Distance that Yoko had travelled until Yoko overtook Eric
= 4 x 80
= 320 km
From 8 a.m. to 1 p.m. = 5 h
Eric's average speed
= 320 ÷ 5
= 64 km/h
(b)
From 9 a.m. to 6:45 p.m. = 9 h 45 min
1 h = 60 min
9 h 45 min = 9
45 60
h = 9
34 h
Distance between the two cities
= 9
34 x 80
=
394 x 80
= 780 km
Answer(s): (a) 64 km/h; (b) 780 km