At 9 a.m., Warren started from City X and travelled towards City Y and his speed remained constant throughout. At 10 a.m., Jade started her journey from City X towards City Y at an average speed of 90 km/h. Jade overtook Warren at 2 p.m. After overtaking, Jade carried on her journey at the same average speed and reached at City Y at 1:30 p.m.

1. Find Warren's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Jade had travelled until Jade overtook Warren
= 4 x 90
= 360 km

From 9 a.m. to 2 p.m. = 5 h

Warren's average speed
= 360 ÷ 5
= 72 km/h

(b)
From 10 a.m. to 1:30 p.m. = 3 h 30 min

1 h = 60 min
3 h 30 min = 3 ³⁰ ₆₀
 h = 3 ¹₂ h

Distance between the two cities
= 3 ¹₂ x 90
= ⁷₂ x 90
= 315 km

Answer(s): (a) 72 km/h; (b) 315 km