At 7 a.m., Caden started from City R and travelled towards City S and his speed remained constant throughout. At 10 a.m., Tina started her journey from City R towards City S at an average speed of 72 km/h. Tina overtook Caden at 1 p.m. After overtaking, Tina carried on her journey at the same average speed and reached at City S at 4:40 p.m.

1. Find Caden's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Tina had travelled until Tina overtook Caden
= 3 x 72
= 216 km

From 7 a.m. to 1 p.m. = 6 h

Caden's average speed
= 216 ÷ 6
= 36 km/h

(b)
From 10 a.m. to 4:40 p.m. = 6 h 40 min

1 h = 60 min
6 h 40 min = 6 ⁴⁰ ₆₀
 h = 6 ²₃ h

Distance between the two cities
= 6 ²₃ x 72
= ²⁰₃ x 72
= 480 km

Answer(s): (a) 36 km/h; (b) 480 km