At 7 a.m., Reggie started from City X and travelled towards City Y and his speed remained constant throughout. At 9 a.m., Wendy started her journey from City X towards City Y at an average speed of 72 km/h. Wendy overtook Reggie at 1 p.m. After overtaking, Wendy carried on her journey at the same average speed and reached at City Y at 1:15 p.m.

1. Find Reggie's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 1 p.m. = 4 h

Distance that Wendy had travelled until Wendy overtook Reggie
= 4 x 72
= 288 km

From 7 a.m. to 1 p.m. = 6 h

Reggie's average speed
= 288 ÷ 6
= 48 km/h

(b)
From 9 a.m. to 1:15 p.m. = 4 h 15 min

1 h = 60 min
4 h 15 min = 4 ¹⁵ ₆₀
 h = 4 ¹₄ h

Distance between the two cities
= 4 ¹₄ x 72
= ¹⁷₄ x 72
= 306 km

Answer(s): (a) 48 km/h; (b) 306 km