At 8 a.m., Oscar started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Pamela started her journey from City T towards City U at an average speed of 72 km/h. Pamela overtook Oscar at 2 p.m. After overtaking, Pamela carried on her journey at the same average speed and reached at City U at 1:40 p.m.

1. Find Oscar's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Pamela had travelled until Pamela overtook Oscar
= 4 x 72
= 288 km

From 8 a.m. to 2 p.m. = 6 h

Oscar's average speed
= 288 ÷ 6
= 48 km/h

(b)
From 10 a.m. to 1:40 p.m. = 3 h 40 min

1 h = 60 min
3 h 40 min = 3 ⁴⁰ ₆₀
 h = 3 ²₃ h

Distance between the two cities
= 3 ²₃ x 72
= ¹¹₃ x 72
= 264 km

Answer(s): (a) 48 km/h; (b) 264 km