At 7 a.m., Fred started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Jaslyn started her journey from City T towards City U at an average speed of 66 km/h. Jaslyn overtook Fred at 1 p.m. After overtaking, Jaslyn carried on her journey at the same average speed and reached at City U at 4:50 p.m.

1. Find Fred's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Jaslyn had travelled until Jaslyn overtook Fred
= 3 x 66
= 198 km

From 7 a.m. to 1 p.m. = 6 h

Fred's average speed
= 198 ÷ 6
= 33 km/h

(b)
From 10 a.m. to 4:50 p.m. = 6 h 50 min

1 h = 60 min
6 h 50 min = 6 ⁵⁰ ₆₀
 h = 6 ⁵₆ h

Distance between the two cities
= 6 ⁵₆ x 66
= ⁴¹₆ x 66
= 451 km

Answer(s): (a) 33 km/h; (b) 451 km