At 7 a.m., Fred started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Jaslyn started her journey from City T towards City U at an average speed of 66 km/h. Jaslyn overtook Fred at 1 p.m. After overtaking, Jaslyn carried on her journey at the same average speed and reached at City U at 4:50 p.m.
- Find Fred's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Jaslyn had travelled until Jaslyn overtook Fred
= 3 x 66
= 198 km
From 7 a.m. to 1 p.m. = 6 h
Fred's average speed
= 198 ÷ 6
= 33 km/h
(b)
From 10 a.m. to 4:50 p.m. = 6 h 50 min
1 h = 60 min
6 h 50 min = 6
50 60
h = 6
56 h
Distance between the two cities
= 6
56 x 66
=
416 x 66
= 451 km
Answer(s): (a) 33 km/h; (b) 451 km