At 8 a.m., Howard started from City U and travelled towards City V and his speed remained constant throughout. At 9 a.m., Pamela started her journey from City U towards City V at an average speed of 72 km/h. Pamela overtook Howard at 2 p.m. After overtaking, Pamela carried on her journey at the same average speed and reached at City V at 5:40 p.m.
- Find Howard's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 2 p.m. = 5 h
Distance that Pamela had travelled until Pamela overtook Howard
= 5 x 72
= 360 km
From 8 a.m. to 2 p.m. = 6 h
Howard's average speed
= 360 ÷ 6
= 60 km/h
(b)
From 9 a.m. to 5:40 p.m. = 8 h 40 min
1 h = 60 min
8 h 40 min = 8
40 60
h = 8
23 h
Distance between the two cities
= 8
23 x 72
=
263 x 72
= 624 km
Answer(s): (a) 60 km/h; (b) 624 km