At 8 a.m., Caden started from City C and travelled towards City D and his speed remained constant throughout. At 10 a.m., Jean started her journey from City C towards City D at an average speed of 78 km/h. Jean overtook Caden at 2 p.m. After overtaking, Jean carried on her journey at the same average speed and reached at City D at 5:30 p.m.

1. Find Caden's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Jean had travelled until Jean overtook Caden
= 4 x 78
= 312 km

From 8 a.m. to 2 p.m. = 6 h

Caden's average speed
= 312 ÷ 6
= 52 km/h

(b)
From 10 a.m. to 5:30 p.m. = 7 h 30 min

1 h = 60 min
7 h 30 min = 7 ³⁰ ₆₀
 h = 7 ¹₂ h

Distance between the two cities
= 7 ¹₂ x 78
= ¹⁵₂ x 78
= 585 km

Answer(s): (a) 52 km/h; (b) 585 km