At 8 a.m., Tom started from City X and travelled towards City Y and his speed remained constant throughout. At 10 a.m., Kylie started her journey from City X towards City Y at an average speed of 90 km/h. Kylie overtook Tom at 1 p.m. After overtaking, Kylie carried on her journey at the same average speed and reached at City Y at 1:20 p.m.

1. Find Tom's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Kylie had travelled until Kylie overtook Tom
= 3 x 90
= 270 km

From 8 a.m. to 1 p.m. = 5 h

Tom's average speed
= 270 ÷ 5
= 54 km/h

(b)
From 10 a.m. to 1:20 p.m. = 3 h 20 min

1 h = 60 min
3 h 20 min = 3 ²⁰ ₆₀
 h = 3 ¹₃ h

Distance between the two cities
= 3 ¹₃ x 90
= ¹⁰₃ x 90
= 300 km

Answer(s): (a) 54 km/h; (b) 300 km