At 7 a.m., Elijah started from City U and travelled towards City V and his speed remained constant throughout. At 9 a.m., Xylia started her journey from City U towards City V at an average speed of 78 km/h. Xylia overtook Elijah at 1 p.m. After overtaking, Xylia carried on her journey at the same average speed and reached at City V at 4:20 p.m.

1. Find Elijah's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 1 p.m. = 4 h

Distance that Xylia had travelled until Xylia overtook Elijah
= 4 x 78
= 312 km

From 7 a.m. to 1 p.m. = 6 h

Elijah's average speed
= 312 ÷ 6
= 52 km/h

(b)
From 9 a.m. to 4:20 p.m. = 7 h 20 min

1 h = 60 min
7 h 20 min = 7 ²⁰ ₆₀
 h = 7 ¹₃ h

Distance between the two cities
= 7 ¹₃ x 78
= ²²₃ x 78
= 572 km

Answer(s): (a) 52 km/h; (b) 572 km