At 8 a.m., Tom started from City R and travelled towards City S and his speed remained constant throughout. At 10 a.m., Winnie started her journey from City R towards City S at an average speed of 90 km/h. Winnie overtook Tom at 1 p.m. After overtaking, Winnie carried on her journey at the same average speed and reached at City S at 1:40 p.m.
- Find Tom's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Winnie had travelled until Winnie overtook Tom
= 3 x 90
= 270 km
From 8 a.m. to 1 p.m. = 5 h
Tom's average speed
= 270 ÷ 5
= 54 km/h
(b)
From 10 a.m. to 1:40 p.m. = 3 h 40 min
1 h = 60 min
3 h 40 min = 3
40 60
h = 3
23 h
Distance between the two cities
= 3
23 x 90
=
113 x 90
= 330 km
Answer(s): (a) 54 km/h; (b) 330 km