At 7 a.m., Simon started from City A and travelled towards City B and his speed remained constant throughout. At 10 a.m., Elyse started her journey from City A towards City B at an average speed of 76 km/h. Elyse overtook Simon at 1 p.m. After overtaking, Elyse carried on her journey at the same average speed and reached at City B at 6:45 p.m.
- Find Simon's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Elyse had travelled until Elyse overtook Simon
= 3 x 76
= 228 km
From 7 a.m. to 1 p.m. = 6 h
Simon's average speed
= 228 ÷ 6
= 38 km/h
(b)
From 10 a.m. to 6:45 p.m. = 8 h 45 min
1 h = 60 min
8 h 45 min = 8
45 60
h = 8
34 h
Distance between the two cities
= 8
34 x 76
=
354 x 76
= 665 km
Answer(s): (a) 38 km/h; (b) 665 km