At 7 a.m., Dylan started from City Q and travelled towards City R and his speed remained constant throughout. At 9 a.m., Marion started her journey from City Q towards City R at an average speed of 84 km/h. Marion overtook Dylan at 1 p.m. After overtaking, Marion carried on her journey at the same average speed and reached at City R at 6:15 p.m.
- Find Dylan's average speed in km/h.
- What is the distance between the two cities?
(a)
From 9 a.m. to 1 p.m. = 4 h
Distance that Marion had travelled until Marion overtook Dylan
= 4 x 84
= 336 km
From 7 a.m. to 1 p.m. = 6 h
Dylan's average speed
= 336 ÷ 6
= 56 km/h
(b)
From 9 a.m. to 6:15 p.m. = 9 h 15 min
1 h = 60 min
9 h 15 min = 9
15 60
h = 9
14 h
Distance between the two cities
= 9
14 x 84
=
374 x 84
= 777 km
Answer(s): (a) 56 km/h; (b) 777 km