At 8 a.m., Brandon started from City C and travelled towards City D and his speed remained constant throughout. At 10 a.m., Anna started her journey from City C towards City D at an average speed of 90 km/h. Anna overtook Brandon at 2 p.m. After overtaking, Anna carried on her journey at the same average speed and reached at City D at 2:50 p.m.

1. Find Brandon's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Anna had travelled until Anna overtook Brandon
= 4 x 90
= 360 km

From 8 a.m. to 2 p.m. = 6 h

Brandon's average speed
= 360 ÷ 6
= 60 km/h

(b)
From 10 a.m. to 2:50 p.m. = 4 h 50 min

1 h = 60 min
4 h 50 min = 4 ⁵⁰ ₆₀
 h = 4 ⁵₆ h

Distance between the two cities
= 4 ⁵₆ x 90
= ²⁹₆ x 90
= 435 km

Answer(s): (a) 60 km/h; (b) 435 km