At 7 a.m., Vaidev started from City H and travelled towards City J and his speed remained constant throughout. At 10 a.m., Winnie started her journey from City H towards City J at an average speed of 88 km/h. Winnie overtook Vaidev at 1 p.m. After overtaking, Winnie carried on her journey at the same average speed and reached at City J at 5:45 p.m.

1. Find Vaidev's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Winnie had travelled until Winnie overtook Vaidev
= 3 x 88
= 264 km

From 7 a.m. to 1 p.m. = 6 h

Vaidev's average speed
= 264 ÷ 6
= 44 km/h

(b)
From 10 a.m. to 5:45 p.m. = 7 h 45 min

1 h = 60 min
7 h 45 min = 7 ⁴⁵ ₆₀
 h = 7 ³₄ h

Distance between the two cities
= 7 ³₄ x 88
= ³¹₄ x 88
= 682 km

Answer(s): (a) 44 km/h; (b) 682 km