At 7 a.m., Warren started from City E and travelled towards City F and his speed remained constant throughout. At 10 a.m., Yoko started her journey from City E towards City F at an average speed of 72 km/h. Yoko overtook Warren at 1 p.m. After overtaking, Yoko carried on her journey at the same average speed and reached at City F at 1:35 p.m.
- Find Warren's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Yoko had travelled until Yoko overtook Warren
= 3 x 72
= 216 km
From 7 a.m. to 1 p.m. = 6 h
Warren's average speed
= 216 ÷ 6
= 36 km/h
(b)
From 10 a.m. to 1:35 p.m. = 3 h 35 min
1 h = 60 min
3 h 35 min = 3
35 60
h = 3
712 h
Distance between the two cities
= 3
712 x 72
=
4312 x 72
= 258 km
Answer(s): (a) 36 km/h; (b) 258 km