At 8 a.m., Jeremy started from City T and travelled towards City U and his speed remained constant throughout. At 10 a.m., Shiyun started her journey from City T towards City U at an average speed of 80 km/h. Shiyun overtook Jeremy at 1 p.m. After overtaking, Shiyun carried on her journey at the same average speed and reached at City U at 1:30 p.m.

1. Find Jeremy's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 1 p.m. = 3 h

Distance that Shiyun had travelled until Shiyun overtook Jeremy
= 3 x 80
= 240 km

From 8 a.m. to 1 p.m. = 5 h

Jeremy's average speed
= 240 ÷ 5
= 48 km/h

(b)
From 10 a.m. to 1:30 p.m. = 3 h 30 min

1 h = 60 min
3 h 30 min = 3 ³⁰ ₆₀
 h = 3 ¹₂ h

Distance between the two cities
= 3 ¹₂ x 80
= ⁷₂ x 80
= 280 km

Answer(s): (a) 48 km/h; (b) 280 km