At 7 a.m., Bryan started from City B and travelled towards City C and his speed remained constant throughout. At 10 a.m., Tiffany started her journey from City B towards City C at an average speed of 84 km/h. Tiffany overtook Bryan at 1 p.m. After overtaking, Tiffany carried on her journey at the same average speed and reached at City C at 3:30 p.m.
- Find Bryan's average speed in km/h.
- What is the distance between the two cities?
(a)
From 10 a.m. to 1 p.m. = 3 h
Distance that Tiffany had travelled until Tiffany overtook Bryan
= 3 x 84
= 252 km
From 7 a.m. to 1 p.m. = 6 h
Bryan's average speed
= 252 ÷ 6
= 42 km/h
(b)
From 10 a.m. to 3:30 p.m. = 5 h 30 min
1 h = 60 min
5 h 30 min = 5
30 60
h = 5
12 h
Distance between the two cities
= 5
12 x 84
=
112 x 84
= 462 km
Answer(s): (a) 42 km/h; (b) 462 km