At 7 a.m., Reggie started from City N and travelled towards City P and his speed remained constant throughout. At 9 a.m., Natalie started her journey from City N towards City P at an average speed of 87 km/h. Natalie overtook Reggie at 1 p.m. After overtaking, Natalie carried on her journey at the same average speed and reached at City P at 1:40 p.m.

1. Find Reggie's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 9 a.m. to 1 p.m. = 4 h

Distance that Natalie had travelled until Natalie overtook Reggie
= 4 x 87
= 348 km

From 7 a.m. to 1 p.m. = 6 h

Reggie's average speed
= 348 ÷ 6
= 58 km/h

(b)
From 9 a.m. to 1:40 p.m. = 4 h 40 min

1 h = 60 min
4 h 40 min = 4 ⁴⁰ ₆₀
 h = 4 ²₃ h

Distance between the two cities
= 4 ²₃ x 87
= ¹⁴₃ x 87
= 406 km

Answer(s): (a) 58 km/h; (b) 406 km