At 8 a.m., Paul started from City E and travelled towards City F and his speed remained constant throughout. At 10 a.m., Victoria started her journey from City E towards City F at an average speed of 81 km/h. Victoria overtook Paul at 2 p.m. After overtaking, Victoria carried on her journey at the same average speed and reached at City F at 1:20 p.m.

1. Find Paul's average speed in km/h.
2. What is the distance between the two cities?

(a)
From 10 a.m. to 2 p.m. = 4 h

Distance that Victoria had travelled until Victoria overtook Paul
= 4 x 81
= 324 km

From 8 a.m. to 2 p.m. = 6 h

Paul's average speed
= 324 ÷ 6
= 54 km/h

(b)
From 10 a.m. to 1:20 p.m. = 3 h 20 min

1 h = 60 min
3 h 20 min = 3 ²⁰ ₆₀
 h = 3 ¹₃ h

Distance between the two cities
= 3 ¹₃ x 81
= ¹⁰₃ x 81
= 270 km

Answer(s): (a) 54 km/h; (b) 270 km