After 35 minutes into a race, Charlie has run ⁷₁₃ of the route while Wesley has covered only ⁴₁₃ of the distance. Charlie runs at the same average speed throughout the race and Wesley’s average speed is 90 m/min slower than Charlie’s. If Wesley wants to finish the race at the same time as Charlie, by how many percent should he increase his average speed by for the remaining part of the race? Round off your answer to the nearest whole number.
Extra distance that Charlie ran more than Wesley in first 35 min
= 35 x 90
= 3150 m

Fraction of the entire distance that was covered by Charlie more than Wesley in the first 35 min
= ⁷₁₃ - ⁴₁₃
= ³₁₃

³₁₃ of the entire distance = 3150 m
¹₁₃ of the entire distance = 3150 ÷ 3 = 1050 m

Distance that Wesley ran in the first 35 min
= 4 x 1050
= 4200 m

Wesley's average speed
= 4200 ÷ 35
= 120 m/min

Charlie's average speed
= 120 + 90
= 210 m/min

Fraction of the journey that Charlie needed to run to complete the race
= 1 - ⁷₁₃
= ⁶₁₃

¹₁₃ of the entire distance = 1050 m
⁶₁₃ of the entire distance = 6 x 1050 = 6300 m

Duration that Charlie would take to complete
= 6300 ÷ 210
= 30 min

Fraction of the journey that Charlie needed to run to complete the race
= 1 - ⁴₁₃
= ⁹₁₃

⁹₁₃ of the entire distance = 9 x 1050 = 9450 m  

Speed that Wesley needs to take to complete distance at the same time as Charlie
= 9450 ÷ 30
= 315 m/min

Increase in Wesley's average speed
= 315 - 120
= 195 m/min

Percentage increase in Wesley's average speed
= ¹⁹⁵₁₂₀ x 100%
≈ 163%

Answer(s): 163%