After 30 minutes into a race, Fred has run ⁶₁₃ of the route while Eric has covered only ⁴₁₃ of the distance. Fred runs at the same average speed throughout the race and Eric’s average speed is 49 m/min slower than Fred’s. If Eric wants to finish the race at the same time as Fred, by how many percent should he increase his average speed by for the remaining part of the race? Round off your answer to the nearest whole number.
Extra distance that Fred ran more than Eric in first 30 min
= 30 x 49
= 1470 m

Fraction of the entire distance that was covered by Fred more than Eric in the first 30 min
= ⁶₁₃ - ⁴₁₃
= ²₁₃

²₁₃ of the entire distance = 1470 m
¹₁₃ of the entire distance = 1470 ÷ 2 = 735 m

Distance that Eric ran in the first 30 min
= 4 x 735
= 2940 m

Eric's average speed
= 2940 ÷ 30
= 98 m/min

Fred's average speed
= 98 + 49
= 147 m/min

Fraction of the journey that Fred needed to run to complete the race
= 1 - ⁶₁₃
= ⁷₁₃

¹₁₃ of the entire distance = 735 m
⁷₁₃ of the entire distance = 7 x 735 = 5145 m

Duration that Fred would take to complete
= 5145 ÷ 147
= 35 min

Fraction of the journey that Fred needed to run to complete the race
= 1 - ⁴₁₃
= ⁹₁₃

⁹₁₃ of the entire distance = 9 x 735 = 6615 m  

Speed that Eric needs to take to complete distance at the same time as Fred
= 6615 ÷ 35
= 189 m/min

Increase in Eric's average speed
= 189 - 98
= 91 m/min

Percentage increase in Eric's average speed
= ⁹¹₉₈ x 100%
≈ 93%

Answer(s): 93%