After 40 minutes into a race, Lee has run ⁸₁₁ of the route while Jack has covered only ²₁₁ of the distance. Lee runs at the same average speed throughout the race and Jack’s average speed is 63 m/min slower than Lee’s. If Jack wants to finish the race at the same time as Lee, by how many percent should he increase his average speed by for the remaining part of the race? Round off your answer to the nearest whole number.
Extra distance that Lee ran more than Jack in first 40 min
= 40 x 63
= 2520 m

Fraction of the entire distance that was covered by Lee more than Jack in the first 40 min
= ⁸₁₁ - ²₁₁
= ⁶₁₁

⁶₁₁ of the entire distance = 2520 m
¹₁₁ of the entire distance = 2520 ÷ 6 = 420 m

Distance that Jack ran in the first 40 min
= 2 x 420
= 840 m

Jack's average speed
= 840 ÷ 40
= 21 m/min

Lee's average speed
= 21 + 63
= 84 m/min

Fraction of the journey that Lee needed to run to complete the race
= 1 - ⁸₁₁
= ³₁₁

¹₁₁ of the entire distance = 420 m
³₁₁ of the entire distance = 3 x 420 = 1260 m

Duration that Lee would take to complete
= 1260 ÷ 84
= 15 min

Fraction of the journey that Lee needed to run to complete the race
= 1 - ²₁₁
= ⁹₁₁

⁹₁₁ of the entire distance = 9 x 420 = 3780 m  

Speed that Jack needs to take to complete distance at the same time as Lee
= 3780 ÷ 15
= 252 m/min

Increase in Jack's average speed
= 252 - 21
= 231 m/min

Percentage increase in Jack's average speed
= ²³¹₂₁ x 100%
≈ 1100%

Answer(s): 1100%