Xylia and Linda started off at the same spot and ran at average speeds round a 2-km circular path. Xylia took 12 minutes to complete each round. Linda completed each round in 25 minutes.
- How far ahead of Linda would Xylia be after 6 minute? Express your answer in metres.
- How long would it take Xylia to meet Linda for the first time?
- How many rounds would Xylia have completed by then?
(a)
Xylia's speed =
212 =
16 km/min
Linda's speed =
225 km/min
Difference in speeds
=
16 -
225=
25150 -
12150=
13150 km/min
Distance between Xylia and Linda after 6 min
= 6 x
13150=
78150 km
1 km = 1000 m
78150 km =
78150 x 1000 = 520
(b)
LCM of 12 and 25 = 300
60 min = 1 h
300 min = 300 ÷ 60 = 5
Xylia and Linda will meet for the first time after 5 h.
(c)
Rounds Xylia completed
= 300 ÷ 12
= 25
Answer(s): (a) 520 m; (b) 5 h; (c) 25