Dylan and Pierre took part in a 16 km marathon. Dylan ran half the distance at a speed of 12 km/h and ran slower for the rest of the way at a speed of 8 km/h. Pierre ran half his total time at 12 km/h and ran slower for the rest of the time at 5 km/h. If they started the marathon at 3.30 a.m., at what time would each of them finish?
- Dylan
- Pierre
(a)
Half of the 16 km marathon = 16 ÷ 2 = 8 km
Time taken by Dylan for the first half of the marathon
= 8 ÷ 12
=
23 h
Time taken by Dylan for the last half of the marathon
= 8 ÷ 8
= 1 h
Total time taken by Dylan
=
23 + 1
= 1
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
1
23 h = 1 h 40 min
1 h 40 min after 3.30 a.m. = 5.10 a.m.
Time that Dylan would finish the marathon = 5.10 a.m.
(b)
Time taken by Pierre for the first half of the marathon
= 8 ÷ 12
=
23 h
Time taken by Pierre for the last half of the marathon
= 8 ÷ 5
= 1
35 h
Total time taken by Pierre
=
23 + 1
35 = 2
415 h
1 h = 60 min
415 h =
415 x 60 = 16 min
2
415 h = 2 h 16 min
2 h 16 min after 3.30 a.m. = 5.46 a.m.
Time that Pierre would finish the marathon = 5.46 a.m.
Answer(s): (a) 5.10 a.m.; (b) 5.46 a.m.