Luis and Owen took part in a 16 km marathon. Luis ran half the distance at a speed of 10 km/h and ran slower for the rest of the way at a speed of 8 km/h. Owen ran half his total time at 10 km/h and ran slower for the rest of the time at 6 km/h. If they started the marathon at 6.30 a.m., at what time would each of them finish?
- Luis
- Owen
(a)
Half of the 16 km marathon = 16 ÷ 2 = 8 km
Time taken by Luis for the first half of the marathon
= 8 ÷ 10
=
45 h
Time taken by Luis for the last half of the marathon
= 8 ÷ 8
= 1 h
Total time taken by Luis
=
45 + 1
= 1
45 h
1 h = 60 min
45 h =
45 x 60 = 48 min
1
45 h = 1 h 48 min
1 h 48 min after 6.30 a.m. = 8.18 a.m.
Time that Luis would finish the marathon = 8.18 a.m.
(b)
Time taken by Owen for the first half of the marathon
= 8 ÷ 10
=
45 h
Time taken by Owen for the last half of the marathon
= 8 ÷ 6
= 1
13 h
Total time taken by Owen
=
45 + 1
13 = 2
215 h
1 h = 60 min
215 h =
215 x 60 = 8 min
2
215 h = 2 h 8 min
2 h 8 min after 6.30 a.m. = 8.38 a.m.
Time that Owen would finish the marathon = 8.38 a.m.
Answer(s): (a) 8.18 a.m.; (b) 8.38 a.m.