Harry and Lee took part in a 16 km marathon. Harry ran half the distance at a speed of 12 km/h and ran slower for the rest of the way at a speed of 8 km/h. Lee ran half his total time at 10 km/h and ran slower for the rest of the time at 6 km/h. If they started the marathon at 7.30 a.m., at what time would each of them finish?
- Harry
- Lee
(a)
Half of the 16 km marathon = 16 ÷ 2 = 8 km
Time taken by Harry for the first half of the marathon
= 8 ÷ 12
=
23 h
Time taken by Harry for the last half of the marathon
= 8 ÷ 8
= 1 h
Total time taken by Harry
=
23 + 1
= 1
23 h
1 h = 60 min
23 h =
23 x 60 = 40 min
1
23 h = 1 h 40 min
1 h 40 min after 7.30 a.m. = 9.10 a.m.
Time that Harry would finish the marathon = 9.10 a.m.
(b)
Time taken by Lee for the first half of the marathon
= 8 ÷ 10
=
45 h
Time taken by Lee for the last half of the marathon
= 8 ÷ 6
= 1
13 h
Total time taken by Lee
=
45 + 1
13 = 2
215 h
1 h = 60 min
215 h =
215 x 60 = 8 min
2
215 h = 2 h 8 min
2 h 8 min after 7.30 a.m. = 9.38 a.m.
Time that Lee would finish the marathon = 9.38 a.m.
Answer(s): (a) 9.10 a.m.; (b) 9.38 a.m.