Cody and Mark took part in a 16 km marathon. Cody ran half the distance at a speed of 10 km/h and ran slower for the rest of the way at a speed of 8 km/h. Mark ran half his total time at 10 km/h and ran slower for the rest of the time at 5 km/h. If they started the marathon at 6.30 a.m., at what time would each of them finish?
- Cody
- Mark
(a)
Half of the 16 km marathon = 16 ÷ 2 = 8 km
Time taken by Cody for the first half of the marathon
= 8 ÷ 10
=
45 h
Time taken by Cody for the last half of the marathon
= 8 ÷ 8
= 1 h
Total time taken by Cody
=
45 + 1
= 1
45 h
1 h = 60 min
45 h =
45 x 60 = 48 min
1
45 h = 1 h 48 min
1 h 48 min after 6.30 a.m. = 8.18 a.m.
Time that Cody would finish the marathon = 8.18 a.m.
(b)
Time taken by Mark for the first half of the marathon
= 8 ÷ 10
=
45 h
Time taken by Mark for the last half of the marathon
= 8 ÷ 5
= 1
35 h
Total time taken by Mark
=
45 + 1
35 = 2
25 h
1 h = 60 min
25 h =
25 x 60 = 24 min
2
25 h = 2 h 24 min
2 h 24 min after 6.30 a.m. = 8.54 a.m.
Time that Mark would finish the marathon = 8.54 a.m.
Answer(s): (a) 8.18 a.m.; (b) 8.54 a.m.