Seth and Zane took part in a 16 km marathon. Seth ran half the distance at a speed of 10 km/h and ran slower for the rest of the way at a speed of 8 km/h. Zane ran half his total time at 12 km/h and ran slower for the rest of the time at 5 km/h. If they started the marathon at 7.30 a.m., at what time would each of them finish?

1. Seth
2. Zane

(a)
Half of the 16 km marathon = 16 ÷ 2 = 8 km

Time taken by Seth for the first half of the marathon
= 8 ÷ 10
= ⁴₅ h

Time taken by Seth for the last half of the marathon
= 8 ÷ 8
= 1 h

Total time taken by Seth
= ⁴₅ + 1
= 1⁴₅ h

1 h = 60 min
⁴₅ h = ⁴₅ x 60 = 48 min
1⁴₅ h = 1 h 48 min

1 h 48 min after 7.30 a.m. = 9.18 a.m.
Time that Seth would finish the marathon = 9.18 a.m.

(b)
Time taken by Zane for the first half of the marathon
= 8 ÷ 12
= ²₃ h

Time taken by Zane for the last half of the marathon
= 8 ÷ 5
= 1³₅ h

Total time taken by Zane
= ²₃ + 1³₅
= 2⁴₁₅ h

1 h = 60 min
⁴₁₅ h = ⁴₁₅ x 60 = 16 min
2⁴₁₅ h = 2 h 16 min
2 h 16 min after 7.30 a.m. = 9.46 a.m.
Time that Zane would finish the marathon = 9.46 a.m.

Answer(s): (a) 9.18 a.m.; (b) 9.46 a.m.