City E and City F are 432 km apart. At 1.48 p.m., Henry is travelling at a uniform speed left City E for City F while Vincent set off from City F to City E along the same road at a uniform speed, which was 8 km/h slower than that of Henry. The two met at 4.48 p.m.

1. Find the speed of Henry.
2. If Vincent continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Henry and Vincent to travel from 1.48 p.m. to 4.48 p.m. = 3 h

Average speed of Henry and Vincent
= 432 ÷ 3
= 144 km/h

Henry's speed
= (144 + 8) ÷ 2
= 152 ÷ 2 
= 76 km/h

(b)
Vincent's speed
= 76 - 8
= 68 km/h

Distance that Vincent travelled in 3 h
= 3 x 68
= 204 km

Remaining distance that Vincent needed to travel
= 432 - 204
= 228 km

Time that Vincent needed to reach his destination after the two met
= 228 ÷ 68
= 3²⁴₆₈
= 3⁶₁₇ h

Answer(s): (a) 76 km/h; (b) 3⁶₁₇ h