City M and City N are 460 km apart. At 4.38 p.m., Bryan is travelling at a uniform speed left City M for City N while Xavier set off from City N to City M along the same road at a uniform speed, which was 10 km/h slower than that of Bryan. The two met at 6.38 p.m.

1. Find the speed of Bryan.
2. If Xavier continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Bryan and Xavier to travel from 4.38 p.m. to 6.38 p.m. = 2 h

Average speed of Bryan and Xavier
= 460 ÷ 2
= 230 km/h

Bryan's speed
= (230 + 10) ÷ 2
= 240 ÷ 2 
= 120 km/h

(b)
Xavier's speed
= 120 - 10
= 110 km/h

Distance that Xavier travelled in 2 h
= 2 x 110
= 220 km

Remaining distance that Xavier needed to travel
= 460 - 220
= 240 km

Time that Xavier needed to reach his destination after the two met
= 240 ÷ 110
= 2²⁰₁₁₀
= 2²₁₁ h

Answer(s): (a) 120 km/h; (b) 2²₁₁ h