City C and City D are 464 km apart. At 3.37 p.m., Owen is travelling at a uniform speed left City C for City D while Caden set off from City D to City C along the same road at a uniform speed, which was 12 km/h slower than that of Owen. The two met at 7.37 p.m.
- Find the speed of Owen.
- If Caden continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Owen and Caden to travel from 3.37 p.m. to 7.37 p.m. = 4 h
Average speed of Owen and Caden
= 464 ÷ 4
= 116 km/h
Owen's speed
= (116 + 12) ÷ 2
= 128 ÷ 2
= 64 km/h
(b)
Caden's speed
= 64 - 12
= 52 km/h
Distance that Caden travelled in 4 h
= 4 x 52
= 208 km
Remaining distance that Caden needed to travel
= 464 - 208
= 256 km
Time that Caden needed to reach his destination after the two met
= 256 ÷ 52
= 4
4852 = 4
1213 h
Answer(s): (a) 64 km/h; (b) 4
1213 h