City Y and City Z are 435 km apart. At 6.56 p.m., Howard is travelling at a uniform speed left City Y for City Z while Valen set off from City Z to City Y along the same road at a uniform speed, which was 5 km/h slower than that of Howard. The two met at 9.56 p.m.
- Find the speed of Howard.
- If Valen continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Howard and Valen to travel from 6.56 p.m. to 9.56 p.m. = 3 h
Average speed of Howard and Valen
= 435 ÷ 3
= 145 km/h
Howard's speed
= (145 + 5) ÷ 2
= 150 ÷ 2
= 75 km/h
(b)
Valen's speed
= 75 - 5
= 70 km/h
Distance that Valen travelled in 3 h
= 3 x 70
= 210 km
Remaining distance that Valen needed to travel
= 435 - 210
= 225 km
Time that Valen needed to reach his destination after the two met
= 225 ÷ 70
= 3
1570 = 3
314 h
Answer(s): (a) 75 km/h; (b) 3
314 h