City M and City N are 418 km apart. At 4.16 p.m., Caden is travelling at a uniform speed left City M for City N while Mark set off from City N to City M along the same road at a uniform speed, which was 11 km/h slower than that of Caden. The two met at 6.16 p.m.
- Find the speed of Caden.
- If Mark continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Caden and Mark to travel from 4.16 p.m. to 6.16 p.m. = 2 h
Average speed of Caden and Mark
= 418 ÷ 2
= 209 km/h
Caden's speed
= (209 + 11) ÷ 2
= 220 ÷ 2
= 110 km/h
(b)
Mark's speed
= 110 - 11
= 99 km/h
Distance that Mark travelled in 2 h
= 2 x 99
= 198 km
Remaining distance that Mark needed to travel
= 418 - 198
= 220 km
Time that Mark needed to reach his destination after the two met
= 220 ÷ 99
= 2
2299 = 2
29 h
Answer(s): (a) 110 km/h; (b) 2
29 h