City J and City K are 468 km apart. At 1.26 p.m., Wesley is travelling at a uniform speed left City J for City K while Albert set off from City K to City J along the same road at a uniform speed, which was 12 km/h slower than that of Wesley. The two met at 4.26 p.m.
- Find the speed of Wesley.
- If Albert continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Wesley and Albert to travel from 1.26 p.m. to 4.26 p.m. = 3 h
Average speed of Wesley and Albert
= 468 ÷ 3
= 156 km/h
Wesley's speed
= (156 + 12) ÷ 2
= 168 ÷ 2
= 84 km/h
(b)
Albert's speed
= 84 - 12
= 72 km/h
Distance that Albert travelled in 3 h
= 3 x 72
= 216 km
Remaining distance that Albert needed to travel
= 468 - 216
= 252 km
Time that Albert needed to reach his destination after the two met
= 252 ÷ 72
= 3
3672 = 3
12 h
Answer(s): (a) 84 km/h; (b) 3
12 h