City S and City T are 440 km apart. At 4.21 p.m., Perry is travelling at a uniform speed left City S for City T while Neave set off from City T to City S along the same road at a uniform speed, which was 10 km/h slower than that of Perry. The two met at 6.21 p.m.
- Find the speed of Perry.
- If Neave continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Perry and Neave to travel from 4.21 p.m. to 6.21 p.m. = 2 h
Average speed of Perry and Neave
= 440 ÷ 2
= 220 km/h
Perry's speed
= (220 + 10) ÷ 2
= 230 ÷ 2
= 115 km/h
(b)
Neave's speed
= 115 - 10
= 105 km/h
Distance that Neave travelled in 2 h
= 2 x 105
= 210 km
Remaining distance that Neave needed to travel
= 440 - 210
= 230 km
Time that Neave needed to reach his destination after the two met
= 230 ÷ 105
= 2
20105 = 2
421 h
Answer(s): (a) 115 km/h; (b) 2
421 h