City B and City C are 540 km apart. At 1.27 p.m., Vaidev is travelling at a uniform speed left City B for City C while Reggie set off from City C to City B along the same road at a uniform speed, which was 10 km/h slower than that of Vaidev. The two met at 4.27 p.m.
- Find the speed of Vaidev.
- If Reggie continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Vaidev and Reggie to travel from 1.27 p.m. to 4.27 p.m. = 3 h
Average speed of Vaidev and Reggie
= 540 ÷ 3
= 180 km/h
Vaidev's speed
= (180 + 10) ÷ 2
= 190 ÷ 2
= 95 km/h
(b)
Reggie's speed
= 95 - 10
= 85 km/h
Distance that Reggie travelled in 3 h
= 3 x 85
= 255 km
Remaining distance that Reggie needed to travel
= 540 - 255
= 285 km
Time that Reggie needed to reach his destination after the two met
= 285 ÷ 85
= 3
3085 = 3
617 h
Answer(s): (a) 95 km/h; (b) 3
617 h