City G and City H are 348 km apart. At 5.18 p.m., Ken is travelling at a uniform speed left City G for City H while Vincent set off from City H to City G along the same road at a uniform speed, which was 6 km/h slower than that of Ken. The two met at 7.18 p.m.
- Find the speed of Ken.
- If Vincent continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Ken and Vincent to travel from 5.18 p.m. to 7.18 p.m. = 2 h
Average speed of Ken and Vincent
= 348 ÷ 2
= 174 km/h
Ken's speed
= (174 + 6) ÷ 2
= 180 ÷ 2
= 90 km/h
(b)
Vincent's speed
= 90 - 6
= 84 km/h
Distance that Vincent travelled in 2 h
= 2 x 84
= 168 km
Remaining distance that Vincent needed to travel
= 348 - 168
= 180 km
Time that Vincent needed to reach his destination after the two met
= 180 ÷ 84
= 2
1284 = 2
17 h
Answer(s): (a) 90 km/h; (b) 2
17 h